You add 50 g of steam at 150 degrees centigrade to 50 g of ice at negative five degrees centigrade. What is the final temperature?
Q = mLfv
Q = mcΔT
The Attempt at a Solution
Qg = Ql
Q1 + Q2 = -Q3 - Q4
mLf + mcΔT = -mLv + mcΔT [ΔT will be negative, making the symbol positive in front]
(0.05)(3.4x105) + (0.05)(4200)(Tf+ 5) = (0.05)(2.26x106) + (0.05)(4200)(Tf - 150)
210Tf + 18 050 = 210Tf -154 600
And I think that here you can see the issue. I asked my instructor since I previously had ...= -mLf - mcΔT, but that gave -232 degrees centigrade.
I'm hoping someone on here can help me. I always get stuck with these problems and the test is in two days, meaning I need to really understand these types of exercises or I'm screwed [these are ranked as the highest marked].
Thanks for any help you can offer!