Gradient and Divergence in spherical coordinates

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physicss
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Homework Statement
Hello, are my answers correct?

I had to calculate the gradient of f=z and f=xy in spherical coordinates.
My solution for f= z is: cos(θ) er+ (-sin(θ)) e(θ)

f=xy

rsin^2(θ)sin(2φ) er+ rcos(θ)cos(φ)sin(θ)sin(φ) e(θ)+ rcos(2φ)sin(θ) e(φ)

I also had to calculate the divergence of the following vectorfield (Image)

My result is: (scalarfield)

Sin^2(θ)cos^2(φ) er + rcos(2θ)cos^2(φ) e(θ)-rsin(θ)cos(2φ) e(φ)


Thanks in advance
Relevant Equations
er, e(θ) and e(φ) are the spherical base vectors
Printed vector field A = (r sin²θ cos²φ) e_r + (r sinθ cosθ cos²φ) e_θ + (−r sinθ sinφ cosφ) e_φ written in spherical coordinates.

Vectorfield for the divergence
 
physicss said:
rsin^2(θ)sin(2φ) er+ rcos(θ)cos(φ)sin(θ)sin(φ) e(θ)+ rcos(2φ)sin(θ) e(φ)
I get a slightly different ##\vec e_\theta##.
Please learn to use LaTeX.
 
physicss said:
My result is: (scalarfield)

Sin^2(θ)cos^2(φ) er + rcos(2θ)cos^2(φ) e(θ)-rsin(θ)cos(2φ) e(φ)
If it is a scalar, how come it has ##\vec e_r## etc?
I also note a dimensional inconsistency.
 
You can get the gradient in spherical (or any other) coordinates by direct substitution, using basic linear algebra. From there you can get div, curl, and the Laplacian just by vector operations: