Graph Curves in the Complex Plane

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Homework Help Overview

The problem involves graphing the locus defined by the equation \(\left|z+2i\right| + \left|z-2i\right| = 6\) in the complex plane. The subject area pertains to complex numbers and their geometric interpretations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the representation of the complex number \(z\) in terms of its real and imaginary parts, leading to the equation involving square roots. There are attempts to manipulate the equation to a more graphable form. Some participants suggest squaring both sides to simplify the expression further.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing guidance on how to approach the manipulation of the equation. The discussion includes recognition of the geometric interpretation of the locus as an ellipse with specified foci.

Contextual Notes

Participants note the geometric properties of the ellipse and the significance of the distances involved in the equation, which may influence the understanding of the problem setup.

msd213
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Homework Statement [/b]

Graph the locus represented by the following.

[tex]\left|z+2i\right| + \left|z-2i\right|[/tex] = 6

Homework Equations





The Attempt at a Solution



z = x + iy so

z-2i = x + (y-2)i and z+2i = x + (y-2)i

So I have:

sqrt(x^2 + (y-2)^2) + sqrt(x^2 + (y+2)^2) = 6

This seems correct but I don't know how to put this in a more manageable form to graph it.
 
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msd213 said:
Homework Statement [/b]

Graph the locus represented by the following.

[tex]\left|z+2i\right| + \left|z-2i\right|[/tex] = 6

Homework Equations





The Attempt at a Solution



z = x + iy so

z-2i = x + (y-2)i and z+2i = x + (y-2)i

So I have:

sqrt(x^2 + (y-2)^2) + sqrt(x^2 + (y+2)^2) = 6

This seems correct but I don't know how to put this in a more manageable form to graph it.

Move one radical to the other side, then square both sides. After doing this, you'll be able to eliminate several terms, and do some other simplification to get one radical on one side. Square both sides again to get this in final form.

The graph you get should be an ellipse with 2i and -2i as the foci.
 
Mark44 said:
Move one radical to the other side, then square both sides. After doing this, you'll be able to eliminate several terms, and do some other simplification to get one radical on one side. Square both sides again to get this in final form.

The graph you get should be an ellipse with 2i and -2i as the foci.

Mark44 knows this because he knows that |a- b|, geometrically, is the distance between the points a and b in the complex plane, and that an ellipse is defined by the property that the total distance from a point on the ellipse to the two foci is a constant.
 
HallsofIvy said:
Mark44 knows this because he knows that |a- b|, geometrically, is the distance between the points a and b in the complex plane, and that an ellipse is defined by the property that the total distance from a point on the ellipse to the two foci is a constant.

Oh! I see now, thank you.
 
HallsofIvy said:
Mark44 knows this because he knows that |a- b|, geometrically, is the distance between the points a and b in the complex plane, and that an ellipse is defined by the property that the total distance from a point on the ellipse to the two foci is a constant.
Right. One definition of an ellipse is that it is the locus of points P such that the sum of the distances from P to two fixed points (the foci) is constant.
 

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