Graph f(2x) with a Simple f(x) Equation

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To graph f(2x) for the function f(x) = x^2, substitute 2x into the equation, resulting in f(2x) = (2x)^2. This transformation indicates that the graph of y = x^2 is horizontally compressed by a factor of 1/2. As a result, points on the original graph are shifted closer to the y-axis, but their vertical values remain unchanged. Understanding this horizontal compression is key to accurately graphing f(2x). The graph will appear "squeezed" horizontally without altering its vertical characteristics.
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Homework Statement


Given f(x) = x^2. Graph f(2x)

Homework Equations



I just need to draw the graph

The Attempt at a Solution



What I tried was putting the x value in the equation which would give me the y value by means of the x^2 part, and the x value would double to give me my new point. This wasn't what the answer key had. Any tips?
 
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When you are asked to find f(2x), you need to substitute 2x as a whole for the original x. Will the value of f(x) really double?
 
it becomes f(2x) = (2x)^2
 
There are two ways to do this. The simplest is to do what theperthvan (and, indirectly, Tedjn) suggests: replace x by 2x. What is (2x)2?

The other is to argue that any change before the "main" function, x2, is applied is a change in x and so changes the graph only horizontally. The value x= 1, after multiplying by 2, becomes the same as x= 2. But 1 is only 1/2 as far from the origin as 2: the whole graph of y= x2 is "squeezed" by 1/2 horizontally but not changed vertically.
 

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