- #1

robertmatthew

- 48

- 0

## Homework Statement

|x| + |y| ≤ 1

What is the region in the plane that solves this inequality?

## Homework Equations

## The Attempt at a Solution

I first tried graphing it by isolating the y variable

|y| ≤ -|x| + 1

Then I looked at the hint we were given, which was to assume that x and y are both positive, so I treated it as if it were written

y ≤ -x+1

And then constructed a graph of a line that was basically y = -x+1 with a domain of [0,3]

But then what threw me off is that the y variable does have the absolute value bars, so there can't be negative y values in the graph, right? So now I'm thinking I just have to flip the part of the graph so that it more closely resembles y=|x-1| in the domain of [0,3]. Is that correct or am I completely missing this?