Graph of f(x,y): Contour Curves & Hyperbolas

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Discussion Overview

The discussion revolves around the function f(x,y) = x² - 2y² and its contour curves. Participants explore whether these curves are hyperbolas or hyperbolic paraboloids, and also delve into finding the tangent plane at a specific point on the surface defined by the function.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant asks about the contour curves of the function and whether they are hyperbolas.
  • Another participant suggests setting x² - y² = k and drawing the curves in the xy-plane to analyze them.
  • Some participants express uncertainty about whether the curves are hyperbolas or hyperbolic paraboloids.
  • A later reply asserts that the surface is a hyperbolic paraboloid and that the contour curves are hyperbolas.
  • Multiple participants inquire about finding the tangent plane at the point (√2, 1, 0) and discuss the derivatives involved, particularly df/dz.
  • One participant points out the ambiguity in considering df/dz since the function does not explicitly include z.
  • Another participant suggests redefining the problem in terms of g(x,y,z) = f(x,y) - z to clarify the derivatives.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the contour curves, with some asserting they are hyperbolas while others consider the possibility of hyperbolic paraboloids. The discussion regarding the tangent plane also reveals uncertainty about the appropriate derivatives to use.

Contextual Notes

There are unresolved questions regarding the definitions and assumptions related to the derivatives, particularly df/dz, and the nature of the curves derived from the function.

evinda
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Hi!
Let the function be f(x,y)=x^2-2*y^2,which graph is S:z=f(x,y).Which are the contour curves?Are these hyperbolas? :confused:

Thanks in advance!:)
 
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put $$x^2-y^2= k $$

Now , choose some values for $k$ and draw them in the xy-plane . What are these curves ?
 
I did this,and I think that the curves are hyperbolas...Is this correct?

- - - Updated - - -

Or are these hyperbolic paraboloids?
 
evinda said:
I did this,and I think that the curves are hyperbolas...Is this correct?

- - - Updated - - -

Or are these hyperbolic paraboloids?

Heh. The surface is a hyperbolic paraboloid.
The contour curves are indeed hyperbolas.
 
Nice...Thank you very much! :p
 
I have also an other question... :o To find the tangent plane at the point (sqrt(2),1,0),I have to find df/dx,df/dy,df/dz...Is df/dz=d(x^2-2*y62-z)/dz=-1?Or df/dz=dz/dz=1?
 
evinda said:
I have also an other question... :o To find the tangent plane at the point (sqrt(2),1,0),I have to find df/dx,df/dy,df/dz...Is df/dz=d(x^2-2*y62-z)/dz=-1?Or df/dz=dz/dz=1?
An equation of the tangent plane to the surface z = f(x, y) at the point P (http://www.math.ucla.edu/~ronmiech/Calculus_Problems/32A/chap12/section4/793d1/IMG00002.GIF is:
http://www.math.ucla.edu/~ronmiech/Calculus_Problems/32A/chap12/section4/793d1/IMG00003.GIF

Regards.
 
Great...!Thank you very much...! :rolleyes:
 
evinda said:
I have also an other question... :o To find the tangent plane at the point (sqrt(2),1,0),I have to find df/dx,df/dy,df/dz...Is df/dz=d(x^2-2*y62-z)/dz=-1?Or df/dz=dz/dz=1?

Well, this is a bit ambiguous.
The surface z=f(x,y) is a parametric surface in x and y.
It makes no sense to consider df/dz which would be zero, since f(x,y) does not contain z.

So I suspect you're supposed to consider g(x,y,z)=f(x,y)-z.
The equation g(x,y,z)=0 identifies the same surface.
And then yes, dg/dz=-1.
 
  • #10
Oh good!Thank you very much! ;)
 
  • #11
You're welcome! ;)
 

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