Graph of Tension force vs. the square of the speed

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Homework Help Overview

The discussion revolves around a physics lab report focused on uniform circular motion, specifically analyzing a graph of Tension Force versus the square of the speed. Participants are exploring the implications of the slope of this graph and its relationship to the variables involved in the experiment.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to identify the independent and dependent variables in the experiment, questioning how varying mass affects the relationship between tension force and speed. There is also a focus on understanding the significance of the slope of the graph.

Discussion Status

The discussion is active, with participants providing insights and prompting further exploration of the relationship between the variables. Some guidance has been offered regarding the connection between the slope and mass, although no consensus has been reached on the exact interpretation of the data.

Contextual Notes

Participants note that the experiment involved varying both mass and speed, which may complicate the analysis of the graph. There is mention of specific equations related to the experiment, but the exact relevance and application of these equations remain under discussion.

rstat1
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Working on a physics lab report regarding uniform circular motion, one of the questions asks to graph the Tension Force vs. the square of the speed. Another part of the same question asks what the slope of the graph represents, which is where I'm stuck.

 
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Your graph, or a table of values would definitely qualify as known data, so you should post those. If you did any theory work before this, you probably also have at least one equation you think is related (IE: one with an acceleration or force term, and a V^2 term). We want to help you work through the problem rather than just giving the answer.
 
FireStorm000 said:
Your graph, or a table of values would definitely qualify as known data, so you should post those. If you did any theory work before this, you probably also have at least one equation you think is related (IE: one with an acceleration or force term, and a V^2 term). We want to help you work through the problem rather than just giving the answer.

My problem was determining what the slope represented. My graph and associated data is in the attached excel file.

As far as equations, I don't even remotely know which would be useful: I've got one for calculating the speed (v = 2pi/T) and one for one for Tension force (M*g)
 

Attachments

My problem was determining what the slope represented. If you still want my graph/data then in its in the attached excel file.

Alright, I took a look at your data and I think I see why you're having trouble. Can you identify the independent and dependent variables in your experiment? It looks like you varied something besides velocity.
 
I only included the data used to make the graph because I thought that was all that was relevant as far as my question was concerned. The experiment focused on timing how long various masses (starting from 50g and going to 135g) would take to make 20 revolutions. So yes I did vary something besides the velocity, the mass was also varied.
 
You should find that the slope has something to do with mass
 
FireStorm000 said:
You should find that the slope has something to do with mass

Well yea I knew that, since the graph is tension force vs speed. I had thought you asked what else I varied.
 
rstat1 said:
Well yea I knew that, since the graph is tension force vs speed. I had thought you asked what else I varied.

Yeah, I was wondering why your graph was all over the place.

The equations you're looking for is:
Actp = r * v 2
and so
Fctp = m * r * v2

Now, I assume r is constant in your setup, so the mass is what changes the ratio of F to V2
Because of that, the slope of any given line segment should show the relative mass between the two data points, if that makes any sense.
 

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