Graphene wavefunction expressed in tight binding form

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SUMMARY

The discussion focuses on the tight binding approximation in graphene, specifically addressing the nature of the wavefunction for atoms A and B. It confirms that the wavefunction is indeed a two-component spinor that describes the entire system rather than individual atoms. The tight binding Hamiltonian is presented, along with its expansion around the Dirac cones, leading to a continuum model that retains the spinorial characteristics of the wavefunction. The relationship between the tight binding model and the continuum model is clarified, emphasizing the delocalized nature of the wavefunction across the graphene lattice.

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  • Tight binding approximation in condensed matter physics
  • Graphene electronic structure and band theory
  • Understanding of spinor wavefunctions
  • Familiarity with Hamiltonian mechanics in quantum systems
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Physicists, materials scientists, and researchers in condensed matter physics who are studying the electronic properties of graphene and the implications of tight binding models on wavefunction behavior.

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TL;DR
Does the wavefunction for A or B atom have the spinorial components (2 components)?
In the framework of tight binding approximation, does the wavefunction for atom A (or B) has two spinorial components(2 components) in "real space"? If so how does this spinorial component propagate in the graphene?
 
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I’m not quite sure what you mean by the wavefunction for an individual atom in graphene. The wavefunction describes the behavior of the whole system, and in a condensed matter system, the real space wavefunction for a given wave vector ##\mathbf{k}## is delocalized over lots of atoms.

Do you maybe mean Wannier functions? These are usually more localized than the eigenfunctions of the Hamiltonian for a condensed matter system.
 
TeethWhitener said:
I’m not quite sure what you mean by the wavefunction for an individual atom in graphene. The wavefunction describes the behavior of the whole system, and in a condensed matter system, the real space wavefunction for a given wave vector ##\mathbf{k}## is delocalized over lots of atoms.

Do you maybe mean Wannier functions? These are usually more localized than the eigenfunctions of the Hamiltonian for a condensed matter system.
Thank you very much for your help, I mean is the tight binding wavefunction (lattice coefficient) at atom A (or B) two-component spinor? If so, how the spinorial lower component propagate? If not, how tight binding wavefunction match the continuum model? In continuum model, the wavefunction evolves between atom A and atom B in two-component spinor form.
 
Ok just to clarify, what the literature calls the continuum model of graphene is the tight binding model, but where you expand the Hamiltonian around the Dirac cones. So the tight binding Hamiltonian looks like
$$H = \begin{pmatrix}
\epsilon & -tf(\mathbf{k}) \\
-tf^*(\mathbf{k}) & \epsilon \\
\end{pmatrix}$$
where
$$f(\mathbf{k}) = \sum_{\mathbf{\delta}}\exp{i\mathbf{k}\cdot\mathbf{\delta}}$$
and the ##\mathbf{\delta}## are the nearest neighbor vectors in real space.
Expanding to first order about the Dirac cone at ##\mathbf{k}=\mathbf{K}## gives:
$$H_{\xi} = \hbar v_F \begin{pmatrix}
0 & \xi k_x-ik_y \\
\xi k_x+ik_y & 0 \\
\end{pmatrix}$$
where we've picked up the valley index ##\xi## which is ##+1## near ##\mathbf{K}## and ##-1## near ##\mathbf{K'}##.
The continuum model allows us to write down the wavefunction explicitly:
$$\psi_{\pm,\xi}=\frac{1}{\sqrt{2}}\begin{pmatrix}
1 \\
\pm\xi e^{i\xi\theta_{\mathbf{k}}}\\
\end{pmatrix} e^{i\mathbf{k}\cdot\mathbf{r}}$$
The spinor nature of this wavefunction doesn't change when you switch to the full tight binding model. (When you say the A/B atoms, I think you're referring to the sublattices of graphene with which each component of the spinor is associated.) But the components of the spinor become functions of ##f(\mathbf{k})##, and I'm not sure if they can be written in closed form.

Did that get a little closer to what you were talking about?
 
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