Graphing Log-Linear Analysis of 2 Exponential Functions

  • Thread starter Thread starter AlexC
  • Start date Start date
  • Tags Tags
    Analysis
Click For Summary
To graph the relationship of two exponential functions on log-linear graph paper, the equation V = Cexp(-t/B) + Aexp(-t/S) needs to be transformed. The challenge lies in determining the parameters B and S simultaneously from the graph. By plotting V against s, where t is expressed as ln(s), the relationship becomes linear, facilitating the extraction of the parameters. This approach allows for a clearer visualization of the exponential decay and aids in parameter estimation. Utilizing this method can simplify the analysis of the combined exponential functions.
AlexC
Messages
1
Reaction score
0
I need to graph a relationship that is the combination of 2 exponential functions on log-linear graph paper.

I have: V = Cexp(-t/B) + Aexp(-t/S)

If it were simply V = Cexp(-t/B) then this wouldn't be a problem (by graphing log(V) = (-1/B)log(e)t + log(C) ) but I need to determine both the B and S parameters (possibly from the same graph). How can i do this?
 
Last edited:
Physics news on Phys.org
If t=ln(s), then V is linear in s...

Plot V vs. s.
 

Similar threads

Replies
12
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K