Graphing Non-f(x) Functions on TI-89 Calculator

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SUMMARY

The TI-89 calculator can graph non-explicit functions, such as implicit equations, by first solving for y. Users can graph equations like 2x + 3y = 7 or 3y² + 2x² - 3x + 6 = 0 by transforming them into explicit forms. The calculator supports parametric graphing, allowing users to represent implicit functions like circles using parameters (e.g., x = cos(t), y = sin(t)). Additionally, the TI-89's programmable capabilities enable users to create custom programs for enhanced graphing functionality.

PREREQUISITES
  • Understanding of implicit and explicit functions
  • Familiarity with the TI-89 calculator interface
  • Basic knowledge of parametric equations
  • Programming skills for TI-89 (optional)
NEXT STEPS
  • Learn how to solve equations for y on the TI-89
  • Explore parametric graphing techniques on the TI-89
  • Research TI-89 programming for custom graphing solutions
  • Investigate graphing inequalities using the TI-89
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Students, educators, and mathematicians who need to graph complex equations and utilize the TI-89 calculator for advanced mathematical functions.

jaredmt
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i was wondering if i could graph something like:
2x + 3y = 7
or
3y^2 + 2x^2 -3x +6 = 0

where the function doesn't always start with plain f(x). is it possible to do this on ti 89?
 
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If y=f(x), then solve for y. If you're asking about things that don't have nice explicit forms, eg a 3rd degree polynomial in y, then yes, the TI-89 can solve those for you.
 
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Fairly sure you can only graph explicit functions on the TI-89, so like qntty says, you'll have to solve for y (but the TI-89 will do this for you).
 
Sometimes, but not always, you can write implicitely defined functions in terms of explicit functions of a parameter. For example, you can graph x2+ y2= 1, a circle, in parametric graphing mode with x= cos(t), y= sin(t).
 
Now the TI-89 is programmable so you might search the TI site for packages you can upload to expand its capacities or write your own. At worst you can graph the inequality f(x,y) < 0 by iterating over the coordinates on the visible screen and plotting the ones satisfying the inequality. The boundary will then be your curve.
 
Yes, if you want to graph an implicit equation without having to first solve for a variable, you could easily write a program to solve it and input it into Y1.
 

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