Graviational Field of Floating Mountain

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SUMMARY

The discussion focuses on calculating the gravitational field intensity difference between the Earth's surface and the top of a spherical mountain of radius a and mass M, which floats in equilibrium with a density half that of the Earth. The solution reveals that the difference in gravitational field intensity, denoted as g0 - g, is given by the formula (GM/a^2)(2 - sqrt(2)). The analysis employs the principle of superposition to relate the gravitational effects of the mountain to that of a thin disk, confirming the equivalence of gravitational fields at the specified point.

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Homework Statement



Consider a spherical mountain of radius a, mass M, floating in equililbrium in the earth, and whose density is half that of the earth. Assume that a is much less than the Earth's radius, so that the Earth's surface can be regarded as flat in the neighborhood of the mountain. If the mountain were not present, the graviational field intensity near the Earth's's surface would be g0. Find the difference between g0 and the actual value of g at the the top of the mountain.

Homework Equations





The Attempt at a Solution



Knowledge of Lagrangian Mechanics is not required. I determined the mountain is half submerged below the Earth's surface and g0 is independent of height (infinite disk). I attempted solving for the g field of a hemisphere but the intergral was not a form that could be solved without binomial expansion. The answer provided in the back of the text is

g0 - g = (GM/a^2)(2 - sqrt(2))

I noted the answer is equivalent to a thin disk of radius a, mass M, with surface density equal to the Earth's volume density at a distance a from the center of the disk along the disk axis. So, somehow superposition shows the equivalence. Any hints are appreciated.
 
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I solved the problem. A matter of superposition of fields at the point in question. Key was finding the field due to a solid hemisphere a distance a from the flat surface of the hemisphere.
 

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