Gravitation energy of a spherical shell

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SUMMARY

The total gravitational energy of a hollow sphere can be calculated using the gravitational field energy density formula, where the energy density is defined as ug = -1/(8πG)g2. By substituting the gravitational field g = Gm/r2, the energy density becomes ug = -GM2/(8πr4). Integrating this expression over the volume yields the total gravitational energy U = -GM2/(2R), confirming the solution's correctness.

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  • Understanding of gravitational field theory
  • Familiarity with the concepts of energy density
  • Knowledge of integration in three-dimensional space
  • Basic principles of gravitational potential energy
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Ananthan9470
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I am asked to find the total gravitational energy of a hollow sphere using the fact that the field energy density is given by ##u_g = \frac{-1}{8\pi G}g^2##.

Now, ##g = \frac{Gm}{r^2}## in this case and substituting gives ##u_g = \frac{-GM^2}{8 \pi r^4}##. Integrating this over volume will give ##U = \iiint \frac{GM^2}{8 \pi r^4} dv = \frac{-GM^2}{2R}##.

Is my solution correct?
 
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Yes, that looks correct.
 

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