Gravitation problem about throwing an object upward

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To determine the maximum height a rock reaches when thrown upward from a small moon, the gravitational acceleration must be calculated using the formula g = GM/r². The kinematic equations typically used for projectile motion on Earth are not applicable here due to the moon's small radius and the significant change in distance during the rock's ascent. Instead, a conservation of energy approach should be employed, utilizing gravitational potential energy as a function of radial distance. This method accounts for the variation in gravitational force as the rock ascends. Proper application of these principles will yield the correct maximum height above the moon's surface.
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Homework Statement


Standing on the surface of a small spherical moon whose radius is 6.00*104 m and whose mass is 7.50*1018 kg, an astronaut throws a rock of mass 2.05 kg straight upward with an initial speed 38.5 m/s. (This moon is too small to have an atmosphere.) What maximum height above the surface of the moon will the rock reach?


Homework Equations



g=GM/r2

The Attempt at a Solution


I calculated g, then used the kinematic equation Δy = (vf2 - vi2) / 2a, but it didn't work! Did I use the wrong equations?
 
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xnitexlitex said:

Homework Statement


Standing on the surface of a small spherical moon whose radius is 6.00*104 m and whose mass is 7.50*1018 kg, an astronaut throws a rock of mass 2.05 kg straight upward with an initial speed 38.5 m/s. (This moon is too small to have an atmosphere.) What maximum height above the surface of the moon will the rock reach?


Homework Equations



g=GM/r2

The Attempt at a Solution


I calculated g, then used the kinematic equation Δy = (vf2 - vi2) / 2a, but it didn't work! Did I use the wrong equations?

Yup. The kinematic equations involving g that we use near the surface of the Earth are valid when g remains essentially constant over the trajectory of the projectile. This holds because the relative change in the radial distance from the center of the Earth is negligible, and g = G*M/r.

For your moon, the radius is relatively small and the upward launch speed will take the projectile a distance that is not negligible with respect to that radius.

You would be better to use a conservation of energy approach, using the appropriate expression for the gravitational potential energy as a function of radial distance.
 
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