Gravitation Problem (Please check my work)

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Homework Help Overview

The problem involves two spherical asteroids made of pure iron that are in contact and exerting a gravitational force on each other. The objective is to determine their diameters in feet such that the force between them is 3 pounds.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of gravitational force equations and the relationship between mass, volume, and density. There are questions regarding the derivation of terms in the equations, particularly the presence of certain constants and the use of density in calculations.

Discussion Status

Several participants have pointed out potential errors in the original poster's calculations, including the treatment of mass and the interpretation of distance between the centers of the spheres. There is an ongoing exploration of the correct application of formulas and units, with some participants offering clarifications on the relationships between radius, diameter, and gravitational force.

Contextual Notes

Participants note that the problem requires the answer in terms of diameters rather than radii, and there is a mention of the challenges posed by the online homework system.

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Homework Statement


Two asteroids are traveling side by side, touching each other. They are both spherical and are made of pure iron. What must their diameters be in feet to exert a force of 3 lb's onto each other?

Homework Equations


V = 4/3*∏*r^3
density of Iron = 7.63*10^3
1 lb = 4.448N
1 foot = .3048 meters
F=Gm1m2/r^2
Vp = Mass

The Attempt at a Solution



So subtitling Vp in for m1 and m2 and then combing the terms since they are equal...
(G(p*4/3*∏*r^3)^2) / 9r^2 = F
(p*G*16*∏^2*r^6 ) / 9r^2 = F
(p*G*16*∏^2*r^4 )/ 9 = F
((F*9) / (p^2*G*16*∏^2)) ^ (1/4) = r

3 lbs = 13.344N
1 ft = .3048m

So I solved this in terms of Newtons and meters then converted the radius to feet and got 12.0 Feet and my online thing is saying it's wrong... this r would be the distance between the COM's so it would equal the diameter of one of them
 
Last edited:
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Why do you get 9r^2 in the denominator? (I assume that you mean "/(9r^2)"). Where does the 9 come from?
Edit: Ah I see. It shouldn't be there in the first line.

What happened to the density? You used the volume as mass...
Work with units, then it is easier to spot mistakes like that.
 
You forgot to use mass = rho * V, where rho is the density of the iron, in your force calculation.

What did you use for G?
 
mfb said:
Why do you get 9r^2 in the denominator? (I assume that you mean "/(9r^2)"). Where does the 9 come from?

The 9 comes from V = (4/3)πr2 after it is squared
 
I actually had p in the formula when I did it, forgot to type... screw statics I thought this class was going to be a breeze but this online homework system is stupid
 
The mistake was forgetting that the distance between the centers of the two spheres is a given sphere's diameter, not the radius (there are two radii between the centers of the spheres: one radius for each sphere!) :smile:

[Edit: other than that your math checks out. :wink:]
 
Last edited:
Oh, that and don't forget that the question is asking for the answer in terms of the spheres' diameters, not their radii. So that's another thing.
 

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