Gravitation with Conservation of Energy and Momentum

Click For Summary
SUMMARY

The discussion focuses on the collision of two spheres with masses M and 2M, released from a distance of 12R. The participants utilize the principles of conservation of energy and momentum to derive the velocities of the spheres upon collision. The gravitational potential energy is expressed as U = (G*M1*M2)/R, and the conservation of momentum is represented by the equation Mv1i + 2Mv2i = Mv1f + 2Mv2f. The challenge lies in expressing v1 in terms of v2 without including the variable R in the final answer.

PREREQUISITES
  • Understanding of gravitational potential energy (U = G*M1*M2/R)
  • Familiarity with conservation of energy and momentum principles
  • Basic algebra for solving equations
  • Knowledge of kinematic equations related to velocity
NEXT STEPS
  • Study the derivation of gravitational potential energy equations
  • Learn how to apply conservation of momentum in collision problems
  • Explore examples of two-body gravitational interactions
  • Practice solving for one variable in terms of another in physics equations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and gravitational interactions, as well as educators looking for examples of conservation laws in action.

blackheart
Messages
9
Reaction score
0
1. Two spheres having masses M and 2M and radii R and 3R, respectively, are simultaneously released from rest when the distance between their centers is 12R. Assume the two spheres interact only with each other and we wish to find the speeds with which they collide. Write an equation from one of the models and solve it for v1, the velocity of the sphere of mass M at any time after release in terms of v2, the velocity of 2M.

2. Homework Equations :

Fg = Gm1m2/r^2

E = K + U

p=mv

3. Do I just use conservation of energy?

Ei = 0 + [G(M)(2M)]/(R^2)

Ef = 1/2Mv1^2 + 1/2(2M)v2^2 + 0

change in E = [1/2Mv1^2 + 1/2(2M)v2^2] - [G(M)(2M)]/(R^2)
This equals 0 since there are no nonconservation forces doing work.
change in E= Wnc = 0

My answer is sqrt(M/36R - 2v2^2) not correct

This is confusing me because it asks for v1 in terms of v2 and I have R in the answer. How do I solve it without R?

I also have to solve this using conservation of momentum.

Mv1i+2Mv2i = Mv1f + 2Mv2f

I don't get how to solve this for v1 in terms of v2 when I don't know initial or final velocities.
 
Physics news on Phys.org
blackheart said:
Fg = Gm1m2/r^2

E = K + U

p=mv

3. Do I just use conservation of energy?

Ei = 0 + [G(M)(2M)]/(R^2)

Ef = 1/2Mv1^2 + 1/2(2M)v2^2 + 0

If you are using conservation of energy to solve this problem, the relevant equation for gravitational potential energy should be U=(G*M1*M2)/R

the R does not have a power 2.

use this to formulate an equation for the U(initial) and U(final).
 
blackheart said:
I also have to solve this using conservation of momentum.

Mv1i+2Mv2i = Mv1f + 2Mv2f

I don't get how to solve this for v1 in terms of v2 when I don't know initial or final velocities.

You do know the initial velocities:

'1. Two spheres having masses M and 2M and radii R and 3R, respectively, are simultaneously released from rest.'

ehild
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
10
Views
3K
Replies
5
Views
3K
  • · Replies 18 ·
Replies
18
Views
1K
Replies
10
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K