1. The problem statement, all variables and given/known data The moon Europa, of the planet Jupiter, has an orbital period of 3.55 days and an average distance from the center of the planet equal to 671,000 km. If the magnitude of the gravitational acceleration at the surface of Jupiter is 2.36 times greater than that on the surface of the Earth, what is the radius of Jupiter? (Hint: begin by calculating the rotation speed.) radius of orbit of Europa, rm = 671000km rotational period of Europa, T = 3.55 days Acceleration due to gravity on Jupiter = GM/r² = 2.36g radius of Jupiter, r = ? 2. Relevant equations Rotational velocity of Europa, ω = 2π/(3.55*86400) radians/second Centripetal acceleration, a =rmω² 3. The attempt at a solution Gravitational acceleration on Europa =GM/(rm)² =(GM/r²)*r²/(rm)² =(2.36g)(r/rm)² Equating gravitational acceleration with centripetal acceleration, (2.36g)(r/rm)² = rmω² r=(rm)³ω²/(2.36g) =74,038 km According to Google, r(Jupiter) = 71,492 km. Did I miss something?