Gravity and Angular acceleration

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Homework Help Overview

The discussion revolves around calculating the angular speed required for a lander to experience an acceleration equivalent to the gravitational acceleration on Europa, a moon of Jupiter. The problem involves concepts from gravitational physics and rotational motion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between centripetal acceleration and gravitational acceleration, questioning the original poster's equations and reasoning. There is a focus on ensuring dimensional consistency in the equations used.

Discussion Status

Some participants have pointed out potential errors in the original poster's approach, particularly regarding the application of gravitational equations and the need to express centripetal acceleration in terms of angular velocity. There is an ongoing examination of the assumptions made in the problem setup.

Contextual Notes

Participants note the importance of unit conversion, specifically the need to convert the diameter of Europa from kilometers to meters. There is also a mention of the relevance of the mass of the object in relation to gravitational acceleration.

sreya
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Homework Statement



There is strong evidence that Europa, a satellite of Jupiter, has a liquid ocean beneath its icy surface. Many scientists think we should land a vehicle there to search for life. Before launching it, we would want to test such a lander under the gravity conditions at the surface of Europa. One way to do this is to put the lander at the end of a rotating arm in an orbiting Earth satellite.

If the arm is 5.25m long and pivots about one end, at what angular speed (in rpm) should it spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa? The mass of Europa is 4.8E22kg and its diameter is 3138 km.

\omega =_____rpm

Homework Equations



v=\omega r

\frac{GMm}{R^2}=a

T = \frac{2\pi}{\omega}

The Attempt at a Solution



\frac{GMm}{R^2}=a

\frac{mv^2}{R}=ma

\frac{\omega^2R}{a}

\omega=\sqrt{\frac{a}{R}}

\omega=\sqrt{\frac{GM}{R_{europa}^2*R_{sat}}}

\frac{60\omega}{2\pi} = x rpm

Edit: Figured out the problem. The diameter of Europa is given in Km, you have to convert it to meters. Stupid Mastering Physics...

Apparently that's not right though??
 
Last edited:
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sreya said:
\frac{GMm}{R^2}=a
... this is not correct: dimensions don't match.

Your reasoning is unclear - you seem to want to put the centripetal acceleration of the station centrifuge equal to the acceleration due to gravity at the surface of Europa.

Try writing centripetal acceleration in terms of angular velocity.
 
Sorry that should be
\frac{GMm}{R^2}=g_{europa}

Which "technically" is still acceleration but that wasn't clear
 
Still not correct.
Dimension still don't match.

Does the acceleration of gravity depend on the mass of the object falling?
Hint: leaning tower of Pisa.

What about writing centripetal acceleration in terms of angular velocity?
 

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