Gravitational and elastic energy

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SUMMARY

The discussion focuses on calculating the necessary length of a spring and mass combined (y) so that when a mass m is hung from a spring with spring constant k, it just touches the floor. The equilibrium length of the spring is denoted as h2, and the height from the floor to the ceiling is h1. The relevant equations used are the elastic energy equation (Ee = kx²/2) and the gravitational energy equation (Eg = mgh). By substituting the extension x into the equations, the solution for y can be derived as y = h1 - h2 - (mgh/k)^(1/2).

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with gravitational potential energy concepts
  • Basic algebra for solving equations
  • Knowledge of energy conservation principles
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  • Study Hooke's Law and its applications in mechanical systems
  • Explore gravitational potential energy calculations in physics
  • Learn about energy conservation in dynamic systems
  • Practice solving problems involving springs and mass systems
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Students studying physics, particularly those focusing on mechanics and energy concepts, as well as educators looking for practical examples of spring dynamics and energy calculations.

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Homework Statement



A spring with spring constant k is hanging from the ceiling, at equilibrium point. The length of the spring in equilibrium is h2. Then you hang a mass less string from the end of the spring, holding a mass m. The length of the string and the mass together equal y.
The height of the floor to the ceiling is h1

Using elastic and gravitational energy equations, what is the necessary length of the spring and the mass combined (y), so that when you hang the mass, it just touches the floor? (in other words, solve for y?)

Homework Equations



Ee=kx2/2

Eg=mgh
 
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If x is the extension in the spring, then
h1 = h2 + x + y.
Substitute the value of x, in the relevant equations and solve for y.
 

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