Gravitational Field Problem - Integrate?

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SUMMARY

The discussion focuses on calculating the gravitational field generated by a nonuniform thin rod of length L, where the mass per unit length varies as λ = Cx. The gravitational field at a point x0, where x0 > L, is derived using the formula Gdm/(x0 - x)², correcting the initial misunderstanding of the variable in the denominator. The integration of the mass element dm is necessary to find the total gravitational field, emphasizing the importance of proper calculus application in physics problems.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F=GMm/d² and g=GM/d².
  • Knowledge of calculus, particularly integration techniques.
  • Familiarity with the concept of mass distribution along a rod.
  • Basic principles of gravitational fields and their calculations.
NEXT STEPS
  • Study the process of integrating variable mass distributions in physics problems.
  • Learn about gravitational field calculations for different mass configurations.
  • Explore advanced calculus techniques relevant to physics, such as integration by parts.
  • Investigate the implications of nonuniform mass distributions on gravitational fields.
USEFUL FOR

Students in physics, particularly those studying gravitational fields, calculus enthusiasts, and educators looking for examples of integrating variable mass distributions in real-world scenarios.

Mmm_Pasta
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Homework Statement


A nonuniform thin rod of length L lies on the x axis. One end of the rod is at the origin, and the other end is at x = L. The rod's mass per unit length λ varies as λ = Cx, where C is a constant. (Thus, an element of the rod has mass dm = λdx.)

Determine the gravitational field due to the rod on the x-axis at x = x0, where x0 > L. (Use the following as necessary: G, M, L, x0.)

Homework Equations



F=GMm/d^2
g=GM/d^2

The Attempt at a Solution


Since the mass varies depending what L is, the equation would be Gdm/(x0-L)^2 which is Gλdx/(x0-L)^2. Do I then integrate to get rid of the dx? If I do I am not sure what dx would be to begin with.
 
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Mmm_Pasta said:

The Attempt at a Solution


Since the mass varies depending what L is, the equation would be Gdm/(x0-L)^2 which is Gλdx/(x0-L)^2.

This looks close, although I think it should be (x0 - x)2 in the denominator, since you are talking about the contribution due to the infinitesimal mass element located at position x.

Mmm_Pasta said:
Do I then integrate to get rid of the dx? If I do I am not sure what dx would be to begin with.

What do you mean by "I don't know what the dx would be to begin with?" :confused: Do you know calculus?
 
I put L because x0 is greater than L, but now I know why it is x. Never mind about the dx; I worded the question wrong, but I know now. Thanks. =)
 
Last edited:

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