If I understand what you're saying here, this is correct. But it's not the final answer.gillyr2 said:Homework Equations
F_tot = F_2 + sqrt(2) * F1
That's just the schematic of the answer. Now you have to figure out F1 & F2 and plug in the numbers. I assume they want an actual answer for the force in Newtons.gillyr2 said:F1 and F3 are the 90 degree forces and F2 is the 45 degree force. what do i still need to do?
The formula for calculating the gravitational force among 4 spheres is: F = G * (m1 * m2 * m3 * m4) / r^2, where G is the gravitational constant, m1-m4 are the masses of the four spheres, and r is the distance between the spheres.
The gravitational force between the four spheres is inversely proportional to the square of the distance between them. This means that as the distance increases, the force decreases, and vice versa.
No, the gravitational force is always attractive between masses. It can only be repulsive if one of the masses has a negative value, which is not possible in this case.
The gravitational constant, denoted by G, is a fundamental constant that relates the strength of the gravitational force to the masses and distances of the objects involved. It is a necessary component of the formula for calculating the gravitational force among 4 spheres.
The Law of Universal Gravitation states that every object in the universe attracts every other object with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The formula for calculating the gravitational force among 4 spheres follows this law, as it takes into account the masses and distances between the four spheres.