Gravitational Force on bathroom scales

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving gravitational force, specifically focusing on how weight changes under different gravitational conditions. The original poster presents a scenario where a person stands on bathroom scales, with questions related to weight on another planet, the planet's radius, and weight at a certain altitude.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of gravitational force equations, questioning the correctness of the original poster's calculations and interpretations. There is a focus on understanding the distinction between mass and weight, especially when considering changes in gravitational field strength.

Discussion Status

Participants are actively engaging with the original poster's calculations, providing feedback and raising questions about the assumptions made. Some guidance has been offered regarding the use of gravitational equations, particularly in relation to the altitude and the mass of the person.

Contextual Notes

There is a noted confusion regarding the terminology used in the problem, particularly the use of "weight" versus "mass." Additionally, the original poster's calculations may lack clarity on how to incorporate altitude into the gravitational equations.

Celer
Messages
13
Reaction score
0
Hi all, I'm new here. So anyways, I have been studying for exams by going through my old tests, and I found a question from one of them that I can't solve...I hope someone can help me.

1. A person stands on a set of bathroom scales which have been calibrates in Newtons. The scales read 500N (assume 3 sig figs)
A)What would the reading be if the same person stood on the scales on a planet where the gravitational field strength, g is 14 N/kg?

B) If this planet had a mass of 7.0 x 10^24 kg, what would its radius be?

C) What mass would this person weigh at an altitude of 2.8 x 10^6 m above the planet's surface?

Homework Equations



Well I used the equations for
A)
F=mg

B)
F = G (mass planet) (mass object) / d^2

C) I don't know what equation to use...


So what I did:

for A) I used Fg=mg
so:

Fg = mg
500 = m (9.8)
m = 51

then I substituted for the planet.

Fg = m(14)
Fg = (51)(14)
Fg = 714

For B) I used F = G (mass planet) (mass object) / d^2
so,

Fg = 6.67 x 10^-9 *7.0x10^24 / d^2
d^2 = 4.669
d = 2160789.4 km

For C) given height, I don't know what equation to use.

So really, I don't know whether I used my equations correctly, so I would appreciate someone to point out my errors.
 
Physics news on Phys.org
Celer said:
C) What mass would this person weigh at an altitude of 2.8 x 10^6 m above the planet's surface?

Hi. The mass of a person should always be constant when he/she moves away from the surface of the planet. I believe the verb "weigh" here does not imply the weight of the person.
 
Celer said:
for A) I used Fg=mg
so:

Fg = mg
500 = m (9.8)
m = 51

then I substituted for the planet.

Fg = m(14)
Fg = (51)(14)
Fg = 714
Looks good.

For B) I used F = G (mass planet) (mass object) / d^2
so,

Fg = 6.67 x 10^-9 *7.0x10^24 / d^2
d^2 = 4.669
d = 2160789.4 km
Did you leave out the mass of the person?

For C) given height, I don't know what equation to use.
Use the same equation that you used for B. What would be the person's distance to the center of the earth?
 
Last edited:
Celer said:
C) What mass would this person weigh at an altitude of 2.8 x 10^6 m above the planet's surface?
I assume that the word mass was an error and that the question should read: What would this person weigh...
 
So, would the mass of the person be unchanged, at 51 kg? I am not sure on what you meant when you said use the same equation as "C".

Do you mean using Fg = mg? If so, how do I factor the given altitude into the equation?
 
Celer said:
So, would the mass of the person be unchanged, at 51 kg?
Yes.
I am not sure on what you meant when you said use the same equation as "C".
Oops... I meant: Use the same equation as used in "B".
 

Similar threads

Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K