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Gravitational Potential Energy of an elevator

  1. Oct 25, 2007 #1
    [SOLVED] Gravitational Potential Energy

    1. The problem statement, all variables and given/known data
    Calculate the change in potential energy of a 77.2-kg man when he takes an elevator from the first floor to 24th floor, if the distance between floors is 4.05 m.


    2. Relevant equations
    Ug = mgy


    3. The attempt at a solution
    Ug = (77.2kg)*(9.81m/s^2)*(24*4.05m) = 73612.67N*m

    What am I doing wrong??
     
  2. jcsd
  3. Oct 25, 2007 #2

    Kurdt

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    If the man travels from the first floor to the second floor how high is he?
     
  4. Oct 25, 2007 #3
    4.05m
     
  5. Oct 25, 2007 #4
    oh nevermind...
     
  6. Oct 25, 2007 #5
    Your equation seems to be correct. I don't see any immediate problem. Just make sure you did not misread or mistype it.
     
  7. Oct 25, 2007 #6

    Kurdt

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    Did you get it or just didn't like my hint?
     
  8. Oct 25, 2007 #7
    LoL...I'm sorry...I got it...I was supposed to do 23*4.05m
     
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