Gravitational Potential Energy on an Incline

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Gravitational Potential Energy (GPE) is typically calculated using the formula U=mgh, where m is mass, g is the acceleration due to gravity, and h is the height above a reference point. On an incline, the height (h) must be measured vertically from the reference point, not along the incline. Therefore, while the formula remains the same, the effective height (h) changes based on the angle of the incline. For an incline at 52 degrees, the vertical height can be calculated using trigonometric functions. Understanding how to determine the correct height is crucial for accurately calculating GPE on an incline.
Travis Enigma
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Homework Statement
What is the Gravitational Potential Energy on an Incline? Is it still mgh?
Relevant Equations
U=mgh
Hi,

When regarding Gravitational Potential Energy, I know the formula is U=mgh. However, when the object is on an incline (say at an angle of 52 degrees) would it still be mgh or something else? (This isn't homework I simply was just curious).
 
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Travis Enigma said:
Homework Statement:: What is the Gravitational Potential Energy on an Incline? Is it still mgh?
Relevant Equations:: U=mgh

Hi,

When regarding Gravitational Potential Energy, I know the formula is U=mgh. However, when the object is on an incline (say at an angle of 52 degrees) would it still be mgh or something else? (This isn't homework I simply was just curious).
Well, whar do the letters m, g, h mean?
 
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Likes Delta2
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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