Potential energy of a block moving up and down an incline.

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SUMMARY

The discussion centers on the potential energy (PE) of a block moving up and down an incline, described by the equation PE = mgh. The potential energy is zero at the base of the incline, reaches a maximum at the top, and decreases back to zero as the block descends. Participants concluded that the graph representing this relationship is parabolic, specifically confirming that option D is correct, as it starts and ends at zero, reflecting the behavior of potential energy over time.

PREREQUISITES
  • Understanding of potential energy and its formula (PE = mgh)
  • Basic knowledge of kinematics, particularly height as a function of time
  • Familiarity with graph interpretation, specifically parabolic graphs
  • Concept of maximum and minimum values in a physical context
NEXT STEPS
  • Study the relationship between height and time in kinematic equations
  • Explore graphical representations of potential energy in physics
  • Learn about energy conservation principles in mechanical systems
  • Investigate the implications of arbitrary zero points in potential energy graphs
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the graphical representation of potential energy in motion.

YMMMA
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Homework Statement


Which graphy represents the potential energy of the block as a function of time?

Homework Equations


PE=mgh

The Attempt at a Solution


First, the potential energy is zero until it reache the top of the incline where the potential energy is maximum. Moving down, the potential energy decreases until zero. But then I am confused is it a parabolic graph like D or linear?
 

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YMMMA said:

Homework Statement


Which graphy represents the potential energy of the block as a function of time?

Homework Equations


PE=mgh

The Attempt at a Solution


First, the potential energy is zero until it reache the top of the incline where the potential energy is maximum. Moving down, the potential energy decreases until zero. But then I am confused is it a parabolic graph like D or linear?
To answer that question, you need to find U(t). Can you do that? Hint: h(t) will do because U(t) = mgh(t).
 
kuruman said:
To answer that question, you need to find U(t). Can you do that? Hint: h(t) will do because U(t) = mgh(t).
Ahh, right the height is proportional to the time squared. So, it’s a parabola.
 
Parabola is correct, but which one of the two shown?
 
D. Since it starts and ends with zero.
 
YMMMA said:
D. Since it starts and ends with zero.
Not a good enough explanation. The zero value for potential energy is (as you know) arbitrary. What if the other graph was labeled so that the potential energy is zero at its end points?
 
kuruman said:
Not a good enough explanation. The zero value for potential energy is (as you know) arbitrary. What if the other graph was labeled so that the potential energy is zero at its end points?
No, it starts with zero, reaches maximum height/ potential energy, and then decrease to zero.
 
Right. The potential energy must exhibit a maximum and must be parabolic.
 
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