# Homework Help: Gravitational Potential Energy Problem

1. Feb 10, 2013

### marc_2094

1. The problem statement, all variables and given/known data
A simple pendulum is swinging. Its mass is m and its length is L. What is its gravitational potential energy if it is oriented at 30° with respect to the vertical? (Let gravitational potential energy be zero if it is in the vertical orientation).

2. Relevant equations
U = mgh

3. The attempt at a solution
Given mass = m and length = L, the only thing left is to solve for h. Since it is oriented 30° wrt vertical, then h = Lcos30°. So U = mgLcos30°

2. Feb 10, 2013

### Staff: Mentor

Hi marc_2094, Welcome to Physics Forums.

Did you draw a diagram showing the pendulum in both orientations? Pay close attention to the location of the line segment that represents the difference in height.

3. Feb 10, 2013

### marc_2094

This is my diagram. Is it correct?

#### Attached Files:

• ###### Untitled.png
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4. Feb 10, 2013

### Staff: Mentor

I don't see the original height (zero reference point for the gravitational potential) indicated, or the line segment representing the change in height.

Mark the original position of the pendulum bob and its new position (at 30°). Is the change in height equal to the length of the triangle leg as you've shown?