Gravitational Potential Energy Problem

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Homework Help Overview

The discussion revolves around a gravitational potential energy problem involving a simple pendulum. The original poster seeks to determine the gravitational potential energy of the pendulum when it is oriented at 30° from the vertical, with the potential energy defined as zero in the vertical position.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of height (h) based on the pendulum's angle and length, with one participant attempting to use the formula U = mgh. Questions arise regarding the accuracy of the height measurement and the representation of the pendulum's positions in a diagram.

Discussion Status

Participants are actively engaging with the problem, with one providing a diagram to illustrate their understanding. There is a focus on clarifying the reference point for gravitational potential energy and ensuring the correct representation of height changes in the pendulum's orientation.

Contextual Notes

There is an emphasis on the importance of accurately defining the reference point for potential energy and the need for clear visual representation in the problem-solving process. Some participants question whether the change in height has been correctly identified in the diagrams presented.

marc_2094
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Homework Statement


A simple pendulum is swinging. Its mass is m and its length is L. What is its gravitational potential energy if it is oriented at 30° with respect to the vertical? (Let gravitational potential energy be zero if it is in the vertical orientation).


Homework Equations


U = mgh


The Attempt at a Solution


Given mass = m and length = L, the only thing left is to solve for h. Since it is oriented 30° wrt vertical, then h = Lcos30°. So U = mgLcos30°

But it's not the answer.
 
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marc_2094 said:

Homework Statement


A simple pendulum is swinging. Its mass is m and its length is L. What is its gravitational potential energy if it is oriented at 30° with respect to the vertical? (Let gravitational potential energy be zero if it is in the vertical orientation).


Homework Equations


U = mgh


The Attempt at a Solution


Given mass = m and length = L, the only thing left is to solve for h. Since it is oriented 30° wrt vertical, then h = Lcos30°. So U = mgLcos30°

But it's not the answer.

Hi marc_2094, Welcome to Physics Forums.

Did you draw a diagram showing the pendulum in both orientations? Pay close attention to the location of the line segment that represents the difference in height.
 
This is my diagram. Is it correct?
 

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marc_2094 said:
This is my diagram. Is it correct?

I don't see the original height (zero reference point for the gravitational potential) indicated, or the line segment representing the change in height.

Mark the original position of the pendulum bob and its new position (at 30°). Is the change in height equal to the length of the triangle leg as you've shown?
 

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