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## Homework Statement

A bit of asteroid material of mass 2.5 x 10^6 kg orbits around the earth at an altitude of 2800km. How long does it take the asteroid to complete one orbit.

M asteroid = 2.5 x 10^6 kg

altitude of asteroid = 2800 km

radius asteroid = 200m

radius earth = 6.37 x 10^6 m

## Homework Equations

Fnet = mv^2/r

C = 2∏r

t = d/v

## The Attempt at a Solution

r = rEarth + rAsteroid + altitude

r = 9.2 x 10^6 m

C = 2∏r

C = 5.78 x 10^7

C = d

Fg = mv^2/r

mg = mv^2/r

9.8 = v^2/r

9.8 (9.2 x 10^6) = v^2

v = 9500 m/s

t = d / v

t = 5.78 x 10^7 / 9500

t = 6084 s

t = 1.7 h

My friend got 0.29 and the teacher had told him he was right. I didn't have a chance to see what I did wrong so I'm wondering if anyone here can tell me where I made my mistake.