Gravitational Pulls- Acceleration decreases as object is farther from center

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SUMMARY

The forum discussion centers on calculating the altitude of a mountain observatory based on a gravimeter's measurement of gravity, which is 0.0057 m/s² less than at sea level. The user, Phoenix, initially used the incorrect mass of the Earth (9.359E17 kg) instead of the correct value (5.98E24 kg) in their calculations. The formula used is g = (GM)/r², where G is the gravitational constant. The user seeks assistance in identifying the error in their altitude calculation, which resulted in an incorrect radius of 2523.4 m.

PREREQUISITES
  • Understanding of gravitational equations, specifically g = (GM)/r²
  • Knowledge of the gravitational constant (G = 6.67E-11 N(m/kg)²)
  • Familiarity with the mass of the Earth (5.98E24 kg)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Review the calculation of gravitational acceleration at different altitudes
  • Learn about the implications of using incorrect constants in physics equations
  • Study the relationship between altitude and gravitational force
  • Explore the use of gravimeters and their applications in geophysics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in gravitational measurements and their applications in determining altitude and geophysical properties.

Phoenixtears
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Homework Statement



A sensitive gravimeter at a mountain observatory finds that the acceleration due to gravity is 0.0057 m/s2 less than that at sea level. What is the observatory's altitude?
___m

Homework Equations



g= (GM)/r^2


The Attempt at a Solution



Alrighty, my attempt makes sense to me, so I'm sure where I'm going wrong.

I began by finding the mass. So, I used 9.8 m/s2 as the g and then the Earth's radius as r:

9.8= (6.67E-11)M/6.37E6 (<----- the Earth's radius)

M= 9.359E17 kg

Then I subtracted the acceleration change given from 9.8:

9.8-0.0057 = 9.7943 m/s2
That is my new g.

Then, using the found mass, I plugged in my new numbers:

9.7943= (6.67E-11)(9.36E17)/ r^2
r=2523.4 m

That, however, was not the correct answer. I can't see my error. Could anyone help me out?

Thanks in advance!

~Phoenix
 
Physics news on Phys.org
Do you need to square the Earth's radius?
 
atyy said:
Do you need to square the Earth's radius?

Sorry. I never came back to edit that out. My mistake. I actually realized that I was being dense and could just use the Earth's mass- 5.98E24.

Yet this is still the incorrect answer. Can anyone help me?
 
We can't tell why your result is incorrect if you don't tell us what your result is and how you obtained it. In other words, show your work, please!
 

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