Gravitational Pulls- Acceleration decreases as object is farther from center

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Homework Help Overview

The problem involves calculating the altitude of a mountain observatory based on a measured decrease in gravitational acceleration compared to sea level. The context is rooted in gravitational physics and the application of the gravitational force equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the observatory's altitude by using the gravitational force equation and adjusting for the change in gravitational acceleration. Some participants question the need to square the Earth's radius in their calculations, while others suggest using the correct mass of the Earth.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the calculations. Guidance has been offered regarding the need to clarify the original poster's results and the methods used to obtain them, indicating a productive direction for further inquiry.

Contextual Notes

There is a lack of clarity regarding the original poster's final result and the specific steps taken in their calculations, which may be contributing to the confusion in the discussion.

Phoenixtears
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Homework Statement



A sensitive gravimeter at a mountain observatory finds that the acceleration due to gravity is 0.0057 m/s2 less than that at sea level. What is the observatory's altitude?
___m

Homework Equations



g= (GM)/r^2


The Attempt at a Solution



Alrighty, my attempt makes sense to me, so I'm sure where I'm going wrong.

I began by finding the mass. So, I used 9.8 m/s2 as the g and then the Earth's radius as r:

9.8= (6.67E-11)M/6.37E6 (<----- the Earth's radius)

M= 9.359E17 kg

Then I subtracted the acceleration change given from 9.8:

9.8-0.0057 = 9.7943 m/s2
That is my new g.

Then, using the found mass, I plugged in my new numbers:

9.7943= (6.67E-11)(9.36E17)/ r^2
r=2523.4 m

That, however, was not the correct answer. I can't see my error. Could anyone help me out?

Thanks in advance!

~Phoenix
 
Physics news on Phys.org
Do you need to square the Earth's radius?
 
atyy said:
Do you need to square the Earth's radius?

Sorry. I never came back to edit that out. My mistake. I actually realized that I was being dense and could just use the Earth's mass- 5.98E24.

Yet this is still the incorrect answer. Can anyone help me?
 
We can't tell why your result is incorrect if you don't tell us what your result is and how you obtained it. In other words, show your work, please!
 

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