Bill_K said:
No it isn't. The "ellipse" in this example has two apogees.
Oops--good point.

Now I have to think up another reason why it isn't a coincidence.

Let's see...
<furrows brow>
Ah, yes, I can't remember where I first came across this argument, but it's pretty straightforward: consider the centripetal acceleration of the person in the circular orbit. (Of course I'm using Newtonian terminology here.) It has a constant magnitude (since the orbital altitude is constant), but its direction changes; relative to the original direction, the one where the circular orbiting person was just passing the person jumping into the tunnel, the circular orbital acceleration is more and more "sideways", until, at the point 90 degrees around the orbit, the acceleration is exactly "sideways", perpendicular to the original direction.
The key question is, how much sideways? Since the orbit is circular, the component in the original direction is just ##cos \phi##, where ##\phi## is the angular coordinate going around the orbit. But ##cos \phi## is just ##r / R##, where ##R## is the radius of the Earth and ##r## is the radial distance to the chord passing through the Earth, perpendicular to the original direction, that intersects the circular orbit (i.e., the Earth's surface) at angle ##\phi## from the original direction.
But ##r / R## is also the ratio of the acceleration of the person who jumps into the tunnel, when he is at radius ##r##, to his starting acceleration, at radius ##R##. (This is, of course, only true on the assumption of a spherical Earth of uniform density.) So basic geometry and trigonometry ensures that both periods will be the same, because the motions of both objects, projected onto the radial line going through the tunnel, are identical--same starting position, velocity, and acceleration, therefore same trajectory.