Gravitational time dilation from the metric

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SUMMARY

The discussion centers on the calculation of gravitational time dilation from the metric, specifically questioning the validity of the formula t'/t_0=1/√g_{tt} for both static and dynamic metrics like the Kerr metric. It is established that while the formula holds for stationary observers in the Kerr metric, the presence of cross terms such as g_{tφ} complicates the situation. The participants emphasize the need for a deeper understanding of how gravitational time dilation is derived from various metrics, particularly in dynamic scenarios.

PREREQUISITES
  • Understanding of general relativity principles
  • Familiarity with metric tensors and their components
  • Knowledge of the Kerr metric and its implications
  • Basic grasp of proper time versus coordinate time
NEXT STEPS
  • Study the derivation of gravitational time dilation in the Schwarzschild metric
  • Explore the implications of the Kerr metric on time dilation
  • Read "Gravitation" by Misner, Thorne, and Wheeler for foundational concepts
  • Investigate the role of cross terms in dynamic metrics
USEFUL FOR

Physicists, students of general relativity, and anyone interested in the effects of gravity on time measurement in both static and dynamic spacetime metrics.

bueller11
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How does one go about finding what the gravitational time dilation is from the metric? Is it simply t'/t_0=1/\sqrt{g_{tt}}? It seems that could be true for static metrics, but perhaps not more dynamic ones like the Kerr metric. My confusion on this arises on how to treat the time cross terms (e.g. the g_{t\phi} term in the Kerr metric).

If that simple formula is not a general truth, will someone point me in the direction of some textbooks or papers that describe how gravitational time dilation is derived from a metric?
 
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Time dilation is the ratio of proper time to coordinate time, dt/dτ, which depends on two things: the world line of the observer, and the choice of time coordinate. In the Kerr metric for a stationary observer (dr = dθ = dφ = 0) you'll have dt/dτ = 1/√gtt, as you said.
 

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