Gravitational time dilation on a non-spherical object

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SUMMARY

The discussion focuses on calculating gravitational time dilation for non-spherical objects, specifically using the formula t = 1/sqrt(1 - 2GM/Rc²). Participants emphasize the complexity of this calculation, noting that it requires generating the energy-momentum tensor and solving Einstein's field equations. For objects with uniform density, the Newtonian gravitational potential can be integrated to find time dilation, but this approach varies with the object's shape. The weak field limit applies primarily to small, low-density objects, such as bricks, while the general relativity framework allows for more complex solutions.

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  • Understanding of general relativity and Einstein's field equations
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  • #31
Dr Chaos said:
Can somebody provide an example with what we have established so far? Just use a brick so I can see how it is done. Thanks.

I don't know a quick answer for this integral; it's rather messy and best handled by mathematical software nowadays.

You could for example use the Wolfram Online integrator to get each of the indefinite integrals in the triple integral and substitute the result into the next one (switching the variable names round cyclically if using the online integrator, as it always assumes dx). For a brick, you could substitute the limits as you do each integration, as the x, y and z limits are independent.
 
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  • #32
relativityfan said:
well this works for metrics like the Reissner Nordstrom metric, but only for static metrics, from what I understand:
in the case of the Kerr metric, there is frame dragging, and there is not only dt^2 in the metric but dt.dphi too

furthermore, at the event horizon of a Kerr black hole, g_rr -> infinite often without g_tt =0
this means that space is infinitely contracted but time is not infinitely dilated, if only g_tt provides the time dilation.
in such case the factor of the time dilation would not be the factor of the length contraction.

in other words, the event horizon is not always the ergosphere

I assumed that this thread was referring to static situations (and outside any event horizon). If the object is at rest relative to the source and the coordinates themselves are static, I think the dt^2 term is all that is needed.
 
  • #34
I've spotted a paper "Gravitational potential and energy of homogeneous rectangular parallelepiped" on the ArXiv which calculates the Newtonian potential for various shapes including a cube and a rectangular shape.

The PDF is at http://arxiv.org/pdf/astro-ph/0002496v1".
 
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  • #35
Here is an example of a comparison of a cube and a sphere based on that paper:

Consider a cube of side 2a with density \rho.

The total volume of the cube is 8 a^3 so its mass is m = 8 a^3 \rho.

The potential at a vertex (corner) of the cube is given in the paper (equation 12) as a multiple of a^2 G \rho (that is, Gm/8a) as follows:

{12 \, \ln \left (\frac{\sqrt{3} + 1}{\sqrt{2}} \right ) - \pi } \approx 4.76

Now consider the potential due to a sphere of the same mass at the same distance from the center as the corner of the cube, that is a \sqrt{3}, in the same units:

\frac{8}{\sqrt{3}} \approx 4.62

This shows that the gravitational effect of a cube is not very different from the effect of a sphere of the same mass produced by smoothing off the corners and pushing the excess material onto the faces.

(The paper seems to quietly ignore the usual convention that the potential expression -Gm/r has a minus sign).
 

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