Gravity and Angular acceleration

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The discussion focuses on calculating the angular speed required for a lander to simulate Europa's gravity using a rotating arm in an Earth satellite. The key equations involve centripetal acceleration and gravitational force, with participants noting the need to convert Europa's diameter from kilometers to meters for accurate calculations. There are concerns about dimensional consistency in the equations used, particularly in equating centripetal acceleration to gravitational acceleration. Suggestions are made to clarify the relationship between angular velocity and centripetal acceleration. The conversation emphasizes the importance of precise calculations and understanding the underlying physics principles.
sreya
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Homework Statement



There is strong evidence that Europa, a satellite of Jupiter, has a liquid ocean beneath its icy surface. Many scientists think we should land a vehicle there to search for life. Before launching it, we would want to test such a lander under the gravity conditions at the surface of Europa. One way to do this is to put the lander at the end of a rotating arm in an orbiting Earth satellite.

If the arm is 5.25m long and pivots about one end, at what angular speed (in rpm) should it spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa? The mass of Europa is 4.8E22kg and its diameter is 3138 km.

\omega =_____rpm

Homework Equations



v=\omega r

\frac{GMm}{R^2}=a

T = \frac{2\pi}{\omega}

The Attempt at a Solution



\frac{GMm}{R^2}=a

\frac{mv^2}{R}=ma

\frac{\omega^2R}{a}

\omega=\sqrt{\frac{a}{R}}

\omega=\sqrt{\frac{GM}{R_{europa}^2*R_{sat}}}

\frac{60\omega}{2\pi} = x rpm

Edit: Figured out the problem. The diameter of Europa is given in Km, you have to convert it to meters. Stupid Mastering Physics...

Apparently that's not right though??
 
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sreya said:
\frac{GMm}{R^2}=a
... this is not correct: dimensions don't match.

Your reasoning is unclear - you seem to want to put the centripetal acceleration of the station centrifuge equal to the acceleration due to gravity at the surface of Europa.

Try writing centripetal acceleration in terms of angular velocity.
 
Sorry that should be
\frac{GMm}{R^2}=g_{europa}

Which "technically" is still acceleration but that wasn't clear
 
Still not correct.
Dimension still don't match.

Does the acceleration of gravity depend on the mass of the object falling?
Hint: leaning tower of Pisa.

What about writing centripetal acceleration in terms of angular velocity?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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