Gravity Equation: Prob 3. Solving Force in Inclined Plane

[patricoles]

Homework Statement

Prob. 3. A block of mass M = 20.0 kg is pushed up a rough inclined plane 37o to the horizontal by a constant force F parallel to the incline as shown. The co-efficient of kinetic friction between the block and the incline is µ = 0.25, and the block is moving up with a constant speed of 2.5 m/s between A and B.

Homework Equations

The Attempt at a Solution

What is the magnitude of F ?
F = 0.25*200cos37 + 200sin37 = 160N
Can you explain the 200sin37 part. Is that gravity can you break it apart
also
gravitational force ? Wg = - 20*200sin37 = - 2400J :
i thought it would be 20*10*20sin37
is gravity force g*m*d where d is the hypotenuse or is the vertical side of the right triangle?

thanks

 

[ideasrule]

You're thinking about gravitational potential energy. 200sin37 is the component of gravity parallel to the ramp.

 

[patricoles]

what about the gravitation force?
- 20*200sin37

is that parallel to the ramp as well?