Block attached to a cord on an inclined plane

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SUMMARY

The discussion focuses on a physics problem involving a block of mass M attached to a cord of mass m on a frictionless inclined plane at angle θ. The objective is to determine the force exerted on the block by the cord while a force F pulls the system up the incline. The equation derived is (M+m)gsinθ - F + Fc = (M+m)a, where Fc represents the force exerted by the cord. The solution requires analyzing both the 'block + rope' system and the block alone to establish a second equation for accurate calculations.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of forces acting on inclined planes
  • Familiarity with free-body diagrams
  • Basic principles of frictionless surfaces
NEXT STEPS
  • Study the concept of free-body diagrams in physics
  • Learn about inclined plane mechanics and force decomposition
  • Explore systems of equations in physics for multi-body problems
  • Review examples of tension in cords and ropes in dynamics
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for problem-solving strategies related to forces on inclined planes.

Cocoleia
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Homework Statement


I have a block of mass M attached to a cord of mass m on an inclined plane of angle θ . A force F is pulling the cord & block up the plane. I have to find the force exerted on the block by the cord. The surface is frictionless

Homework Equations


F = ma

The Attempt at a Solution


So far I have tried to figure all of the forces that are acting on the system and place them in the F=ma equation. This is what I have come up with:
(M+m)gsinθ-F+Fc=(M+m)a
where Fc is the force exerted by the cord.
Otherwise, I am unsure of how to proceed.
 
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Cocoleia said:
This is what I have come up with:
(M+m)gsinθ-F+Fc=(M+m)a
It's not clear what system you are analyzing with this equation.

Do this: Analyze the 'block + rope' system; get a force equation. Then analyze the block alone to get your second equation.
 

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