What Happens to Lost Gravitational Energy in Degenerate Matter?

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SUMMARY

The discussion centers on the behavior of gravitational energy in degenerate matter, specifically within white dwarfs. When a white dwarf loses gravitational potential energy (GPE) during contraction, this energy is not simply lost but is transformed. The energy that does not contribute to overcoming electron degeneracy pressure is converted into heat as the star stabilizes after contraction. This process highlights the conservation of energy principle in astrophysical contexts.

PREREQUISITES
  • Understanding of gravitational potential energy (GPE)
  • Knowledge of electron degeneracy pressure
  • Familiarity with the properties of white dwarfs
  • Basic principles of thermodynamics in astrophysics
NEXT STEPS
  • Research the mechanisms of energy conversion in stellar objects
  • Study the role of electron degeneracy in stellar stability
  • Explore the thermodynamic processes in white dwarfs
  • Investigate the implications of energy conservation in astrophysical systems
USEFUL FOR

Astronomers, astrophysicists, and students studying stellar evolution will benefit from this discussion, particularly those interested in the dynamics of white dwarfs and energy transformations in degenerate matter.

cepheid
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Okay, I noticed that my OP got 39 views but no responses, so let me change my strategy. Here is my question:

An object made out of degenerate matter (e.g. white dwarf) will collapse if more gravitational energy is lost in getting smaller than the energy that is gained due to electron degeneracy. So, the sum of these two energies will decrease. But total energy must be conserved. So, what happens to the rest of the GPE that is lost (the part that doesn't go into doing work to overcome degeneracy pressure during contraction)? Is it just converted to heat?

My OP is below if you want more details on what I'm asking about.

My prof. was giving a sort of heuristic outline of how the Chandrasekhar mass limit arises. He started with the basic "equilibrium equation" that the energy E = Ekin + Epot should be minimized. This is in the context of a "cold" object, where most of "Ekin" is due to electron degeneracy. In other words, there is no thermal pressure support. All of the support against gravity comes from degeneracy pressure. He then worked out how each of these energies varies with the volume (or radius) of the object, and showed that in the case of non-relativistic electrons, there is an equilibrium point (the sum of the energies E is minimized for some finite radius R), and in the relativistic case, there is no global minimum, the solution is unchecked collapse. I looked into this further, and I realized that another way to think about this is in terms of pressure balance. You can equate the "gravitational pressure" to the negative of the degeneracy pressure, where

Pgrav = -∂Epot/∂V

and

Pdeg = -∂Ekin/∂V

This equation of pressures results in

∂(Epot + Ekin) / ∂V = 0

showing that pressure balance does indeed occur at a minimum in the sum of the energies.

Here is my question: in the situation where collapse occurs, gravitational pressure exceeds degeneracy pressure, meaning that the rate of change of Epot and Ekin with radius (or volume) is such that more GPE is lost in contracting than the energy that is gained due to electron degeneracy. In other words, not all of the GPE that is lost is "used up" in doing work against degeneracy pressure. The sum E is actually reduced. But total energy must be conserved right? The sum E must not be the total energy of the system. So what happens to the rest of that GPE?

An obvious answer would seem to be: "it is converted into heat." Is that the case? If so, then I have another related question...
 
Last edited:
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It's converted to kinetic energy from ordered inward directed motion in the first place. If the star settles down again, it would become heat.
 
Heh, inwardly directed motion. How did I miss that?
 

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