GRE Test Question Homework: Is (n^*)^* = n?

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SUMMARY

The GRE practice question involves the operation defined as n^* = 32 - n, where the asterisk represents a specific operation rather than an exponent. The discussion clarifies that (n^*)^* equals n, as it simplifies to m^* where m = 32 - n. The key takeaway is that the operation is a subtraction from 32, not an exponentiation, leading to the conclusion that the two values are indeed equal as stated in the answer key.

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Homework Statement



Hi,
I was doing some GRE practice tests and came across this question:

for all number n, n^*=32-n (apparently where the asterisk is an exponent)

They then give me two values, which are (n^*)^* and n, and I am to say whether choice 1 is a greater value than choice 2, choice 2 is a greater value than choice 1, the two values are equal, or there is not enough info to determine. The answer key says they are equal. This means given the above equation, (n^*)^* = n

I can't see how this is true... Anyone care to explain? Thanks
 
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Let n^*=32-n=m. Then, (n^*)^*=m^*. Can you evaluate m^*?
 
cristo said:
Let n^*=32-n=m. Then, (n^*)^*=m^*. Can you evaluate m^*?

I'm not sure. Is there some way you want me to rewrite this? m^*=(32-n)^*
 
Xkaliber said:
I'm not sure. Is there some way you want me to rewrite this? m^*=(32-n)^*

Yes. The star is shorthand for the operation that "subtracts a given number from 32." In the case of m^*, the given number is 32-n. What is the result when you apply * to that?
 
lol, that was easy. I had in my mind that * was some sort of exponential value, not a more general operator. Thanks
 

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