Greatest integer function limit problem. Proving whether the limit exists

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SUMMARY

The limit of the function as x approaches 1 is proven to exist, with both the right-hand limit and left-hand limit yielding a value of 4. The expression evaluated is lim (5 - 1/2[[2x]]) as x approaches 1, where [[2x]] represents the greatest integer function, also known as the floor function. The calculations confirm that the limit is consistent from both directions, affirming the existence of the limit at this point.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with the greatest integer function (floor function)
  • Basic algebraic manipulation skills
  • Knowledge of one-sided limits
NEXT STEPS
  • Study the properties of the greatest integer function (floor function)
  • Learn about one-sided limits in calculus
  • Explore limit proofs and techniques in calculus
  • Practice evaluating limits involving piecewise functions
USEFUL FOR

Students studying calculus, particularly those focusing on limits and the greatest integer function, as well as educators seeking to clarify these concepts for learners.

johnjrgs
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Homework Statement


Prove that the limit exists.
lim 5 - 1/2[[2x]]
x-->1
Show your solution..

Homework Equations





The Attempt at a Solution


Tried getting the limit from the right and left.. not sure if what I've done is right though but this is what I got.

lim 5 - 1/2[[2x]] ===> 5-1/2(2(1)) ====> 4
x-->1+

lim 5 - 1/2[[2x]] ===> 5-1/2(2(1)) ====> 4
x-->1-

The answer I got is equal in both ways, therefore the limit exists.

If I'm wrong tell me where and help me please.
 
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It would help if you told us what [[x]] meant! I thought it might be the "floor function" but if that were true then for 0< x< 1, [[2x]] would be 0, not 2, so the lower limit would be 5, not 4.
 

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