Group theory and quantum mechanics

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The discussion focuses on deriving complete basis functions using group theory, specifically applying it to the triangle group for CH3Cl. It emphasizes that the system's symmetries are crucial, as group representation theory is applicable only when symmetry is present. The user has successfully symmetrized the basis functions and is now working on finding the eigenvalues from a block diagonal matrix. A question arises regarding the treatment of a 3x3 off-diagonal matrix within the larger 5x5 matrix, seeking guidance on how to proceed with it. Understanding the relationship between the basis functions and the eigenfunctions in this context is essential for further analysis.
journeyman1986
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How to you get sets of complete basis functions using group theory ? For example , using triangle group for CH3 Cl ?
 
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The question's so general, you can write books about the answer. It has to do with the system's set of symmetries. If there's no symmetry, there's no group representation theory.
 
Hi , I misunderstood the question sorry about that . I am new to group theory and quantum mechanics. Anyway,
I did the problem and got the symmetrized basis functions .
Next step would be to find the eigenvalues. The matrix I have is in block diagonal form.
\left(
\begin{array}{ccccc}
\left(
\begin{array}{c}
\beta
\end{array}
\right) & \left(
\begin{array}{c}
-\delta
\end{array}
\right) & \left(
\begin{array}{c}
-\sqrt{3} \gamma
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) \\
\left(
\begin{array}{c}
-\delta
\end{array}
\right) & \left(
\begin{array}{c}
\epsilon
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) \\
\left(
\begin{array}{c}
-\sqrt{3} \gamma
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
-2 \alpha
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) \\
\left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
\alpha
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) \\
\left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
0
\end{array}
\right) & \left(
\begin{array}{c}
\alpha
\end{array}
\right)
\end{array}
\right)
My question would be ? The basis functions from the 2-D representation looks like they are eigenfunctions but what about the 3*3 matrix that are in off diagonal form in the 5*5 matrix ? What do I do with that ?
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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