I would let time $t=0$ be at 1/2 year ago, and let $W$ be measured in millions of dollars. Then I would state the IVP:
$$\frac{dW}{dt}=k\sqrt{W}$$ where $$W(0)=1,\,W\left(\frac{1}{2}\right)=4$$
Separating variables and using the boundaries as limits, we have:
$$\int_1^{W} u^{-\frac{1}{2}}\,du=k\int_0^t\,dv$$
$$2\left[u^{\frac{1}{2}}\right]_1^{W}=k[v]_0^t$$
$$2\left(\sqrt{W}-1\right)=kt$$
Since $k$ is a constant, we can divide through by 2 and still have a constant:
$$\sqrt{W}-1=kt$$
$$W(t)=(kt+1)^2$$
Now, using the second point to determine $k$
$$\left(\frac{k}{2}+1\right)^2=4$$
$$\frac{k}{2}+1=2$$
$$k=2$$
Hence:
$$W(t)=(2t+1)^2$$