Hi. I have coefficient of x2 as
in an expression that looks like this
* calculator shows little yellow triangle because 'x' is not defined.
If I can write the coefficient of x2 as - 0.091372213746554 then why did the author write coefficient of x2 like this shown below?
Thanks.
Mod note: Fixed all of the radicals. The expressions inside the radical need to be surrounded with braces -- { }
(This question is probably asked a lot but I could not find it so I'll just ask it myself.)
Does the square root of negative numbers exist in the complex field? In other words is...
In this Khan Academy video
they say that it is ok to break the square root ##\sqrt{a\cdot b}##, with ##a, b \in \mathbb{R}##, into the product of two square roots ##\sqrt{a}\cdot \sqrt{b}##, only when: (1) both are non negative, (2) one of the two is negative and the other is possitive. I...
Homework Statement
Homework Equations
The Attempt at a Solution
I tried using the rule of multiplying with the "conjugate", for example what's above multiplied by (√n^3+3n)+(√n^3+2n^2+3)/(√n^3+3n)+(√n^3+2n^2+3).
But I'm left with a huge mess :(
I also tried dividing the top and the bottom...
Homework Statement
##\frac{x+\sqrt3}{\sqrt{x}+\sqrt{x+\sqrt3}} + \frac{x-\sqrt3}{\sqrt{x}-\sqrt{x-\sqrt3}} = \sqrt{x}##
All real solutions to this equation are found in the set:
##a) [\sqrt3, 2\sqrt3), b) (2\sqrt3, 3\sqrt3), c) (3\sqrt3, 6), d) [6, 8)##
Homework Equations
3. The Attempt at a...
I am trying to use a numerical polynomial root finding method, but I am unsure of the order of an expression. For example, if I have something that looks like
x2+5x √(x2+3)+x+1=0
what is the coefficient of the second order (and potentially even the first order) term? Is the entire 5x√... term...