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[H+] and pH of 100 mM solution of KOH

  1. Oct 6, 2009 #1
    1. The problem statement, all variables and given/known data
    What is [H+] and pH for a 100 mM solution of KOH


    3. The attempt at a solution

    This seems very simple..its only 2 marks but I dont know what I'm doing wrong.

    I understand KOH will dissociate into K+ and OH-

    pOH=-log(OH) ?
    ph + pOH = 14
    p[OH]=-log[100x10^-6?]
    where and what am i doing wrong?

    Thanks for the help!!
     
  2. jcsd
  3. Oct 6, 2009 #2

    Borek

    User Avatar

    Staff: Mentor

    milli is not 10-6.

    --
    methods
     
  4. Oct 6, 2009 #3
    I thought it was micro lol
     
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