Lower pH w/ Equal Vol 0.60M NaOH: 0.70 M KOH

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Discussion Overview

The discussion revolves around a homework problem concerning the effect of adding an equal volume of 0.60 M NaOH to various solutions and determining which would result in a lower pH. The solutions in question include water, 0.30 M HCl, 0.70 M KOH, and 0.40 M NaNO3. Participants explore the implications of adding a strong base to these solutions.

Discussion Character

  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant asserts that adding 0.60 M NaOH to 0.70 M KOH results in a lower pH due to a left shift in the equilibrium.
  • Another participant argues that adding a strong acid, such as 0.30 M HCl, would increase the H+ concentration and decrease the OH- concentration, thus lowering the pH.
  • A participant expresses confusion, stating that adding NaOH to any solution should increase the pH, not decrease it.
  • Another participant suggests that there may be a misunderstanding of the question, indicating that acid is not being added in the scenario.
  • A later reply acknowledges a moment of realization regarding the misunderstanding of the problem.

Areas of Agreement / Disagreement

Participants exhibit disagreement regarding the interpretation of the problem and the effects of adding NaOH to the different solutions. There is no consensus on which solution would lead to a lower pH.

Contextual Notes

Some participants may be missing assumptions about the behavior of strong acids and bases in solution, and there is a lack of clarity on how the addition of NaOH interacts with the existing concentrations of H+ and OH- in the various solutions.

ThatDude
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Homework Statement


To which of the following would the addition of an
equal volume of 0.60 M NaOH lead to a solution
having a lower pH? (a) water, (b) 0.30 M HCl,
(c) 0.70 M KOH, (d) 0.40 M NaNO3.

2.The attempt at a solution
t
he correct answer is 0.70 M KOH, and they say that by adding more OH you are producing a left shift. Okay, that's cool.

My answer is 0.30 M HCl, this is because adding a strong acid will increase H+ concentration, OH- concentration will go down, therefore pH will decrease. Why is this wrong?
 
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ThatDude said:

Homework Statement


To which of the following would the addition of an
equal volume of 0.60 M NaOH lead to a solution
having a lower pH? (a) water, (b) 0.30 M HCl,
(c) 0.70 M KOH, (d) 0.40 M NaNO3.

2.The attempt at a solution
t
he correct answer is 0.70 M KOH, and they say that by adding more OH you are producing a left shift. Okay, that's cool.

My answer is 0.30 M HCl, this is because adding a strong acid will increase H+ concentration, OH- concentration will go down, therefore pH will decrease. Why is this wrong?

You might have misread the question: acid is not being added.
 
Perhaps I am missing something, but I don't get the question - in each case after adding NaOH pH goes up, it never goes down, thus it can't be lower.
 
I think you are slightly missing it. :oldwink:
 
Geez, got it. What a brain fart o0)
 

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