Lower pH w/ Equal Vol 0.60M NaOH: 0.70 M KOH

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In summary, the conversation is discussing which of the given solutions would have a lower pH when an equal volume of 0.60 M NaOH is added. The correct answer is 0.70 M KOH, as adding more OH- ions causes a left shift in the equilibrium, resulting in a lower pH. The incorrect answer of 0.30 M HCl is based on the misunderstanding that adding a strong acid would decrease pH, when in fact it increases H+ concentration and raises the pH.
  • #1
ThatDude
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Homework Statement


To which of the following would the addition of an
equal volume of 0.60 M NaOH lead to a solution
having a lower pH? (a) water, (b) 0.30 M HCl,
(c) 0.70 M KOH, (d) 0.40 M NaNO3.

2.The attempt at a solution
t
he correct answer is 0.70 M KOH, and they say that by adding more OH you are producing a left shift. Okay, that's cool.

My answer is 0.30 M HCl, this is because adding a strong acid will increase H+ concentration, OH- concentration will go down, therefore pH will decrease. Why is this wrong?
 
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  • #2
ThatDude said:

Homework Statement


To which of the following would the addition of an
equal volume of 0.60 M NaOH lead to a solution
having a lower pH? (a) water, (b) 0.30 M HCl,
(c) 0.70 M KOH, (d) 0.40 M NaNO3.

2.The attempt at a solution
t
he correct answer is 0.70 M KOH, and they say that by adding more OH you are producing a left shift. Okay, that's cool.

My answer is 0.30 M HCl, this is because adding a strong acid will increase H+ concentration, OH- concentration will go down, therefore pH will decrease. Why is this wrong?

You might have misread the question: acid is not being added.
 
  • #3
Perhaps I am missing something, but I don't get the question - in each case after adding NaOH pH goes up, it never goes down, thus it can't be lower.
 
  • #4
I think you are slightly missing it. :oldwink:
 
  • #5
Geez, got it. What a brain fart o0)
 

1. What is the meaning of "Lower pH w/ Equal Vol 0.60M NaOH: 0.70 M KOH"?

The phrase "Lower pH w/ Equal Vol 0.60M NaOH: 0.70 M KOH" refers to a chemical solution where the pH level is lowered by adding equal volumes of a 0.60 M solution of sodium hydroxide (NaOH) and a 0.70 M solution of potassium hydroxide (KOH).

2. What is the purpose of using equal volumes of NaOH and KOH in this solution?

The purpose of using equal volumes of NaOH and KOH is to neutralize each other and create a balanced pH level. This allows for more precise control over the pH of the solution.

3. How does the pH level change when adding equal volumes of NaOH and KOH?

The pH level will decrease when adding equal volumes of NaOH and KOH because both are strong bases. This is because strong bases have a higher concentration of hydroxide ions (OH-) which can neutralize hydrogen ions (H+) and lower the pH level.

4. What is the concentration of the resulting solution after adding equal volumes of NaOH and KOH?

The resulting solution will have a concentration of 0.65 M (0.60 M + 0.70 M / 2) after adding equal volumes of NaOH and KOH. This is because the concentrations of both solutions are averaged when mixed together in equal volumes.

5. What are the potential applications of using this solution with a lower pH?

This solution can be used in various applications such as water treatment, industrial processes, and laboratory experiments. It can also be used to adjust the pH of acidic solutions, making them more neutral or basic.

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