Hall Effect: Calculating Drift Velocity, Depth & Magnetic Field

[farshad147]

hi everyone,
first of all, sorry for my bad english!

I've got a computer project from my physics teacher which is about hall effect,

the problem says that we have: Drift velocity "Vd" , Depth of the plate "d" and magnetic field "B",
now we want to calculate 2 things:

first: changing of voltage per time
second: final voltage

 

[James98765]

I am not an expert when it comes to Hall voltage but I am familiar with the general concept. To derive the Hall voltage equation, begin with the magnetic force:

F_m = q v B where q is the charge, v is the velocity, and B is the magnetic field strength

F_m = e v_d B with q = e and v = v_d

The magnetic force acting on the flowing electrons is equal to the electric force created by the Hall effect. Electric force is given by:

F_e = e E where E is the electric field strength
F_e = e V/d where V is the hall voltage and d is the depth

Setting F_m = F_e gives:
e v_d B = e V/d

Therefore the hall voltage is:
V = d v_d B

Using the above equation, the Hall voltage can be calculated from depth d, drift velocity v_d, and magnetic field strength B.

You asked to calculate the "change in voltage per time" and I'm not quite sure how to answer that question. To the best of my knowledge, hall voltage is constant so the change per time should be zero. (Assuming a constant depth, drift velocity, and magnetic field strength.) The "final voltage", or in my opinion "constant voltage", is given by the last equation. Just substitute in the values.

Let me know if you need more clarification.