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Hamiltonian Kinetic Energy Operator

  1. Dec 12, 2012 #1
    In the QM Hamiltonian, I keep seeing h-bar/2m instead of p/2m for the kinetic energy term. H-bar is not equivalent to momentum. What am I missing here?
  2. jcsd
  3. Dec 12, 2012 #2
    Actually, gang, I did a little more fishing and came across the answer to my question. For anyone that's interested, here's the link.


    Look under this section: Kinetic energy in quantum mechanics
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