Hammer Projectile Motion: Time and Range Calculations.

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SUMMARY

The discussion focuses on calculating the time and range of a hammer dropped from a roof at a constant speed of 4 m/s, with the roof inclined at 30 degrees and 10 meters above the ground. The time taken to hit the ground is calculated as 1.239 seconds, while the horizontal range is determined to be 4.291 meters. The correct formula for vertical motion is confirmed to be y = y(initial) + v(y)t + 0.5gt², emphasizing the importance of including the t² term in the equation.

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Homework Statement



A worker on the roof of a house drops his hammer, which slides down the roof at a constand speed of 4 m/s. The roof makes an angle of 30 degrees with the horizontal, and its lowest point is 10 m from the ground.

A-find the time it takes to hit the ground
b- what is the range

Homework Equations



v(x) = 4cos-30 = 3.464
v(y) = 4sin-30 = -2

The Attempt at a Solution



Just want someone to verify my work

y = y(initial) + v(y)t + .5gt
0 = 10 - 2t - 4.9t, t = 1.239s

x = x(initial) + v(x)t
x = 3.464(1.239) = 4.291 m
 
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Your solution is correct.
But in the equation
y = y(initial) + v(y)t + .5gt
it should by
y = y(initial) + v(y)t + .5gt^2
 

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