HAPPY HOLIDAYS Arrangements and Fraction Calculation

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The discussion focuses on calculating the number of distinct arrangements of the phrase "HAPPY HOLIDAYS," which consists of 13 letters with specific repetitions. The formula used to determine the arrangements is A = 13! / (2!)^4, accounting for the repeated letters. Participants congratulated members who provided the correct solution, which involves multiplying A by the fraction 503/97297200. The final calculated result is 2012. This calculation highlights the application of combinatorial principles in solving arrangement problems.
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Let A be the number of distinct arrangements of "HAPPY HOLIDAYS" (don't consider the space to be a character).

What is [math]A \times \frac{503}{97297200}[/math]?
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Congratulations to the following members for their correct solution:

1) Sudharaka
2) MarkFL
3) soroban
4) veronica1999

Solution (from Sudharaka):[sp]The following is the list of letters in "Happy Holidays" and the number of times each letter appears.

H - 2, A - 2, P - 2, Y - 2, O - 1, L - 1, I - 1, D - 1, S - 1

Number of letters in "Happy Holidays" = 13

Therefore the number of possible arrangements (A) = \(\dfrac{13!}{(2!)^4}\)

\[\therefore A \times \frac{503}{97297200}=\frac{13!}{(2!)^4}\times\frac{503}{97297200}=2012\][/sp]
 

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