Harmonic Motion: Calculating Speed in Simple Harmonic Motion

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SUMMARY

The discussion focuses on calculating the speed of a rider on a mechanical bull undergoing simple harmonic motion (SHM). The bull has a mass of 200 kg, an amplitude of 2.70 m, and a frequency of 0.342 Hz. To determine the upward speed at which the rider leaves the saddle, one must equate the upward force from SHM with gravitational force, utilizing the equations F=ma and F=mg. The velocity can then be calculated using the energy equation 1/2kA^2 = 1/2mv^2 + 1/2ky^2.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Familiarity with Newton's laws of motion
  • Knowledge of energy conservation principles
  • Ability to manipulate equations involving force and motion
NEXT STEPS
  • Study the principles of simple harmonic motion in depth
  • Learn how to derive the equations of motion for SHM
  • Explore the relationship between frequency, amplitude, and energy in SHM
  • Investigate real-world applications of SHM in mechanical systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and harmonic motion, as well as educators looking for practical examples of SHM applications.

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Homework Statement



While visiting friends at Cal State Chico, you pay a visit to the Crazy Horse Saloon. This fine establishment features a 200- kg mechanical bucking bull that has a mechanism that makes it move vertically in simple harmonic motion. Whether the “bull” has a rider or not, it moves with the same amplitude 2.70 m and frequency 0.342 Hz. Being from Texas you decide to ride it the “macho” way by NOT holding on. To no ones surprise you go flying out of the saddle. While waiting for your bruises and pride to heal, you decide to calculate how fast upward you were moving when you left the saddle.

Give your answer in m/s to the second decimal place.

Homework Equations



I do not even know where to start on this one any help would greatly be appreciated

The Attempt at a Solution



same as above
 
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You have to determine the y-position at which you fly off the saddle. When does the force pushing you up (due to simple harmonic motion) equal the force of gravity?

Hint: use [tex]F=ma[/tex] and [tex]F=mg[/tex]. You'll need to use the fact that [tex]a=w^2y[/tex].

When you have this, you can find your velocity using the energy equation:
[tex]1/2kA^2 = 1/2mv^2 + 1/2ky^2[/tex]

Does this help?
 
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