- #1
dustybray
- 10
- 0
Hi,
I'm having trouble with this problem because I don't know how to deal with all these unknowns:
4. A block attached to a spring with unknown spring constant oscillates with a period of 2.0 s. What is the period if :
a. The mass is doubled?
b. The mass is halved?
c. The amplitude is doubled?
d. The spring constant is doubled?
I think I should use T = 2π * sqrt( m / k ), but what are m and k... ??
Also, what relates this to amplitude?
Hopefully I'm doing this problem correctly, but I don't know how to get acceleration:
7. The bow of a destroyer undergoes simple harmonic vertical pitching motion with a period of 8.0 s and an amplitude of 2.0 m.
a. What is the maximum vertical velocity of the destroyer’s bow?
f = 1/T = .125rev/s
ω = 2πf = .785rad/s
v = ωr = (.785rad/s) (2m) = 1.57m/s
b. What is the maximum acceleration?
??
c. An 80 kg sailor is standing on a scale in the bunkroom in the bow. What are the maximum and minimum readings on the scale in Newtons?
80kg * ( 9.8m/s^2 + a)
80kg * ( 9.8m/s^2 - a)
Thanks,
dusty...
I'm having trouble with this problem because I don't know how to deal with all these unknowns:
4. A block attached to a spring with unknown spring constant oscillates with a period of 2.0 s. What is the period if :
a. The mass is doubled?
b. The mass is halved?
c. The amplitude is doubled?
d. The spring constant is doubled?
I think I should use T = 2π * sqrt( m / k ), but what are m and k... ??
Also, what relates this to amplitude?
Hopefully I'm doing this problem correctly, but I don't know how to get acceleration:
7. The bow of a destroyer undergoes simple harmonic vertical pitching motion with a period of 8.0 s and an amplitude of 2.0 m.
a. What is the maximum vertical velocity of the destroyer’s bow?
f = 1/T = .125rev/s
ω = 2πf = .785rad/s
v = ωr = (.785rad/s) (2m) = 1.57m/s
b. What is the maximum acceleration?
??
c. An 80 kg sailor is standing on a scale in the bunkroom in the bow. What are the maximum and minimum readings on the scale in Newtons?
80kg * ( 9.8m/s^2 + a)
80kg * ( 9.8m/s^2 - a)
Thanks,
dusty...