Confused about a simple harmonic motion problem....

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Homework Help Overview

The discussion revolves around a vertical block-spring system and its period of oscillation on Earth compared to the Moon, specifically addressing the influence of gravitational acceleration on the period of the system.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between gravitational acceleration and the period of a spring-mass system, with some asserting that gravity does not affect the period. Others question the validity of the answer key suggesting a different period on the Moon.

Discussion Status

The discussion is ongoing, with participants expressing confusion over the answer key's claim and exploring the implications of gravitational differences on the system's behavior. Some participants provide insights into the nature of oscillation and equilibrium positions.

Contextual Notes

There is mention of a discrepancy between the original poster's findings and the answer key, as well as a request for additional information about the source material related to the problem.

Jordan Jones
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Homework Statement


A vertical block-spring system on Earth has a period of 6.0 s. What is the period of this same system on the moon where the acceleration due to gravity is roughly 1/6 that of earth?

Homework Equations


w = √(k/m)
w = (2Pi)/T
T = 2Pi*√(m/k)[/B]

The Attempt at a Solution


So I solved for the period using the first two equations and found that g does not play a role in the equation. From this I said that the period of the spring should stay the same on the mood because the acceleration due to gravity does not affect the period.

The answer key for the problem says 15 seconds but I have no idea how.

Any help here? Confused.
 
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Jordan Jones said:
found that g does not play a role in the equation. From this I said that the period of the spring should stay the same on the mood because the acceleration due to gravity does not affect the period.
Quite right.
Jordan Jones said:
The answer key for the problem says 15 seconds
Sounds like someone is confusing springs and pendulums.
 
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I think that your answer key has it wrong. The period depends only on the mass and the spring constant.

My suggestion: burn the book and get another one :smile:
 
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Jordan Jones said:

Homework Statement


A vertical block-spring system on Earth has a period of 6.0 s. What is the period of this same system on the moon where the acceleration due to gravity is roughly 1/6 that of earth?

Homework Equations


w = √(k/m)
w = (2Pi)/T
T = 2Pi*√(m/k)[/B]

The Attempt at a Solution


So I solved for the period using the first two equations and found that g does not play a role in the equation. From this I said that the period of the spring should stay the same on the mood because the acceleration due to gravity does not affect the period.

The answer key for the problem says 15 seconds but I have no idea how.

Any help here? Confused.

Can you give us the full title, author/s, publisher, and publish date of the text that this came from?

BTW, to follow up with the question, the only difference that you see when you bring this spring-mass system to the moon is that the equilibrium position is different. The frequency and consequently, the period, of oscillation remain the same, as you have noted.

Zz.
 

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