A spring holds a weight of 800 g. The spring is set in a harmonious swing. The frequency f for the oscillation is 1.4 Hz. When the weight is 5 cm above the equilibrium position on the way upwards, a velocity of 1.1 m / s is noted
a) Determine the amplitude of the movement.
b) What is the acceleration when the weight is 2 cm above the equilibrium?
f = 1/T
MV^2/2 + kY^2/2=kA^2/2
The Attempt at a Solution
I first attempted to calculate the amplitude of the movement by using the first equation but since i didn't have the time of the spring i crossed over that calculation, i latet tried using the 2 later equations together but i never managed to get a resonable result from my calculation
The English in the question might be a bit wrong, not my mother tongue so i had to translate the question from Swedish so bare with me :)
Any help is appreciated! Thanks in advance
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